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^2-7V+6=2V^2+12V-14
We move all terms to the left:
^2-7V+6-(2V^2+12V-14)=0
We add all the numbers together, and all the variables
-7V-(2V^2+12V-14)=0
We get rid of parentheses
-2V^2-7V-12V+14=0
We add all the numbers together, and all the variables
-2V^2-19V+14=0
a = -2; b = -19; c = +14;
Δ = b2-4ac
Δ = -192-4·(-2)·14
Δ = 473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{473}}{2*-2}=\frac{19-\sqrt{473}}{-4} $$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{473}}{2*-2}=\frac{19+\sqrt{473}}{-4} $
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